Anyone?

[End]

Was wondering if anyone could solve this.

Good luck!


19 + 9 = 82
13 + 5 = 52
10 + 6 = 46
7 + 8 = 43
6 + 4 = 28
5 + 3= ?

[kingW3]

5+3=22?

[End]

Both correct, don't know how you did it so fast, took me much, much longer to figure it out.

Well done!

[kingW3]

Well i did it like this
since f(x)=kx+y
f(28)=28k+y=82
f(18)=18k+y=52
now 28k+y=82
       -18k-y=-52
10k=30(Solved system of linear equations)
k=3
from the first one
28k+y=82
84+y=82
y=-2
so
f( 8 )=8k+y OR 24-2=22
Though i'm not sure how efko did it.

[.SaLiH.]

asdf pro maths

[div.ide]

Do you know why I hate this kind of riddles?

My first thought was "cool, maybe it's some exotic position system like base17".

... Nope. Just muliplied result. Wasted time looking for wrong answer

[kingW3]

I doubt that in any base system where 13+5 is equal to 52, 19+9 is eqaul to 82
Unless maybe if you add some zeroes but still i doubt

[div.ide]

It was just an example yeah, I immediately realised different base systems would have more sense if it involved some letters.

[FU I am PeNGuiN]

riddles like this sucks, everyone can make a pattern and make one on its own, so only thing you need is to be fast

[CoMMoN1337]

Was wondering if anyone could solve this.

Good luck!


19 + 9 = 82
13 + 5 = 52
10 + 6 = 46
7 + 8 = 43
6 + 4 = 28
5 + 3= ?

The arithmetic stands 1+1=1+1, regardless of the context. The only exception to this is different base math. If there is some subjective or personal standard by which the numerical "value" of a strawberry is found, then this does not invalidate the arithmetic. Instead, it invalidates our initial formation of one or more of the addends which constitute the addition problem - i.e., if we agree on these added conditions (pun intended) and replace the incorrect values with the appropriate ones, the solution is 8.

More simply put (for you to understand, since you are so inferior), (yeah i'm mocking you, congratulations, you figured it out) It's just an exercise with variables to be found, however you attributed a value on the left side of the "=" which doesn't "=" the right side of the "=", and taking into account the fact that it's not a different base math (this being something which would justify apparent misscoordination, since it's not really misscoordination, it's just a different base math), that means you are not allowed to use the same form of notation.

Even more simply put (since i have absolutely no doubt that some of you still don't get it), you used numbers with other values than their own, but also used their own original value in the same exercise without anything to distinguish between the 2 values. That is not allowed. 19+9 is not 82, 13+5 is not 52, 10+6 is not 46, 7+8 is not 43 6+4 is not 28, 5+3 is not 22. You should've used variables if you wanted to propose any kind of legitimate exercise.

I have no doubt that you posted it this way because of two alternatives, which can be made into a single one if combined.
1. It's not your exercise and you simply copied it
2. You/whomever made it, wanted it to appear "interesting" or other such bullshit concept. Well you/whomever succeded in doing so, you/whomever made it interesting indeed. Interestingly preposterous that is.

Taking into account what i said in the previous paragraphs, your problem is not worth solving since it's incoherent babbling.

[CoMMoN1337]

Oh, there is another alternative i haven't considered.
+1 post count.
Speaking of which, i just did the same thing, feels good.

Feel free to merge this post fully with my previous one.